(sec5(3x)tan5(3x))dx\int(sec^5(3x)tan^5(3x)) dx

asked by guest
on Mar 30, 2025 at 9:30 pm



You asked:

Evaluate the integral: sec(3x)5tan(3x)5dx\int{{\sec\left( 3 x \right)}^{5} {\tan\left( 3 x \right)}^{5}}dx

MathBot Answer:

Antiderivative

sec(3x)5tan(3x)5dx=3563cos4(3x)+90cos2(3x)945cos9(3x)+C\int{{\sec\left( 3 x \right)}^{5} {\tan\left( 3 x \right)}^{5}}dx = - \frac{-35 - 63 \cos^{4}{\left(3 x \right)} + 90 \cos^{2}{\left(3 x \right)}}{945 \cos^{9}{\left(3 x \right)}} + C