$\frac{\6x+6}{\2x-1}$ - 2
asked by guest on Apr 01, 2025 at 10:35 am
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MathBot Answer:
6x+62x−1−2=−2+6x+62x−1\displaystyle \frac{6 x + 6}{2 x - 1} - 2 = -2 + \frac{6 x + 6}{2 x - 1} 2x−16x+6−2=−2+2x−16x+6
6x+62x−1−2=6x2x−1−2+62x−1\frac{6 x + 6}{2 x - 1} - 2 = \frac{6 x}{2 x - 1} - 2 + \frac{6}{2 x - 1}2x−16x+6−2=2x−16x−2+2x−16
6x+62x−1−2=2(x+4)2x−1\frac{6 x + 6}{2 x - 1} - 2 = \frac{2 \left(x + 4\right)}{2 x - 1}2x−16x+6−2=2x−12(x+4)
