[{10*(12/4-1)-2}-{(6*6-6)/2}]/3

asked by guest
on Jan 26, 2025 at 10:08 pm



You asked:

Evaluate the expression: \(\frac{10 \left(\frac{12}{4} - 1\right) - 2 - \frac{6 \cdot 6 - 6}{2}}{3}\)

MathBot Answer:

\[\frac{10 \left(\frac{12}{4} - 1\right) - 2 - \frac{6 \cdot 6 - 6}{2}}{3} = 1\]

\[\begin{aligned}\frac{10 \left(\frac{12}{4} - 1\right) - 2 - \frac{6 \cdot 6 - 6}{2}}{3}& = \left(10 \cdot \left(\frac{12}{4} - 1\right) - 2 - \left(6 \cdot 6 - 6\right) \cdot \frac{1}{2}\right) \cdot \frac{1}{3}\\& = \left(10 \cdot 2 - 2 - \left(6 \cdot 6 - 6\right) \cdot \frac{1}{2}\right) \cdot \frac{1}{3}\\& = \left(20 - 2 - \left(6 \cdot 6 - 6\right) \cdot \frac{1}{2}\right) \cdot \frac{1}{3}\\& = \left(20 - 2 - \left(36 - 6\right) \cdot \frac{1}{2}\right) \cdot \frac{1}{3}\\& = \left(20 - 2 - \frac{30}{2}\right) \cdot \frac{1}{3}\\& = \left(20 - 2 - 15\right) \cdot \frac{1}{3}\\& = \left(18 - 15\right) \cdot \frac{1}{3}\\& = \frac{3}{3}\\& = 1\end{aligned}\]

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