log x + log(x+9)=1

asked by guest
on Nov 17, 2024 at 11:25 am



You asked:

Solve the equation \(\log\left( x \right) + \log\left( x + 9 \right) = 1\) for the variable \(x\).

MathBot Answer:

The 2 solutions to the equation are: \[\begin{aligned}x &= - \frac{9}{2} + \frac{\sqrt{81 + 4 e}}{2} \approx 0.29252353\\x &= - \frac{9}{2} - \frac{\sqrt{81 + 4 e}}{2} \approx -9.2925235\end{aligned}\]


\(e\) is Euler's number, a mathematical constant that is approximately \(2.71828\).