22(X+150)+71x=26565

asked by guest
on Apr 06, 2025 at 5:47 am



You asked:

Investigate the equation: 22(X+150)+71x=2656522 \left(X + 150\right) + 71 x = 26565.

MathBot Answer:

The graph of 22(X+150)+71x=2656522 \left(X + 150\right) + 71 x = 26565 is a line.

The X-intercept is 21152\frac{2115}{2}.

The x-intercept is 2326571\frac{23265}{71}.

The slope of the line is 2271- \frac{22}{71}.

The slope-intercept form of the line is x=232657122X71x = \frac{23265}{71} - \frac{22 X}{71}.

The line in standard form is 22X+71x23265=0 22 X + 71 x - 23265 = 0

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