y=x^⅔+0.9sin(kx)√(3-x²) when k=100

asked by guest
on Nov 23, 2024 at 10:38 am



You asked:

Solve the system of equations:y=x23+0.9sin⁡(kx)⋅3−x2k=100\begin{aligned}y &= {x}^{\frac{2}{3}} + 0.9 \sin\left( k x \right) \cdot \sqrt{3 - {x}^{2}}\\k &= 100\end{aligned}

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