1=x^2+2xy+y^2 solve for y

asked by guest
on Apr 02, 2025 at 7:32 pm



You asked:

Solve the equation 1=x2+2xy+y21 = {x}^{2} + 2 x y + {y}^{2} for the unknown yy.

MathBot Answer:

y=1−xy=−x−1\begin{aligned}y &= 1 - x\\y &= - x - 1\end{aligned}

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