inverse function of y = x^2 + 3x + 4

asked by guest
on Nov 17, 2024 at 2:00 pm



You asked:

Find the inverse of \(y = {x}^{2} + 3 x + 4\)

MathBot Answer:

For \(-\infty \lt x \le - \frac{3}{2}\) the inverse is \(y = - \frac{\sqrt{4 x - 7}}{2} - \frac{3}{2}\)
For \(- \frac{3}{2} \le x \lt \infty\) the inverse is \(y = \frac{\sqrt{4 x - 7}}{2} - \frac{3}{2}\)

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