make d the subject of the equation
\frac{1}{d}+c=\frac{b}{d}\:\:
asked by guest on Apr 07, 2025 at 3:31 am
You asked:
MathBot Answer:
d=b−1c\begin{aligned}d &= \frac{b - 1}{c}\end{aligned}d=cb−1 and d≠0d \neq 0d=0