log√y^3+logx^3-log√x^3z^4÷log1.2=(3÷2)

Given that x=2, y =3, z= 5

asked by guest
on Nov 19, 2024 at 5:40 am



You asked:

Solve the system of equations:log⁡(y3)+log⁡(x3)−log⁡(x3z4)log⁡(1.2)=32x=2y=3z=5\begin{aligned}\log\left( {\sqrt{y}}^{3} \right) + \log\left( {x}^{3} \right) - \frac{\log\left( {\sqrt{x}}^{3} {z}^{4} \right)}{\log\left( 1.2 \right)} &= \frac{3}{2}\\x &= 2\\y &= 3\\z &= 5\end{aligned}

MathBot Answer:

The system of equations has no solution.

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