13+nb-(b)-1.962=0

na=nb*m

13*0.6-(a)*0.9-na*0.9=0

asked by guest
on Oct 18, 2024 at 7:34 am



You asked:

Solve the system of equations:\[\begin{aligned}13 + n b - b - 1.962 &= 0\\n a &= n b m\\13 \cdot 0.6 - a \cdot 0.9 - n a \cdot 0.9 &= 0\end{aligned}\]

MathBot Answer:

The system of equations has infinitely many solutions.

$$\begin{aligned}a &= \frac{26}{3}\\b &= \frac{5519}{500}\\n &= 0\end{aligned}$$

\(m\) is a free variable.

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