$$\sum_{k=1}^{n}{4k}=2(n^{2}+n )$$

asked by guest
on Sep 22, 2024 at 12:23 pm



You asked:

Investigate the equation: \(\sum_{k = 1}^{n} {4 k} = 2 \cdot \left({n}^{2} + n\right)\).

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