Math Problem Solver

\[ 7\frac{1}{8} + 2\frac{3}{8} = \frac{19}{2} = 9.5 \]

The sum can be computed by rewriting each term over a common denominator, where the least common denominator of \(\frac{7}{1}\), \(\frac{1}{8}\), \(\frac{2}{1}\), and \(\frac{3}{8}\) is \(8\). \[ \begin{aligned} 7\frac{1}{8} + 2\frac{3}{8} &= \frac{7 \cdot 8}{1 \cdot 8} + \frac{1 \cdot 1}{8 \cdot 1} + \frac{2 \cdot 8}{1 \cdot 8} + \frac{3 \cdot 1}{8 \cdot 1} \\ &= \frac{56 + 1 + 16 + 3}{8} \\ &= \frac{76}{8} \\&= \frac{19}{2} \end{aligned} \]