16x^2 - 1
asked by guest on Mar 23, 2025 at 12:34 am
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MathBot Answer:
16x2−1=16x2−1\displaystyle 16 {x}^{2} - 1 = 16 x^{2} - 1 16x2−1=16x2−1
16x2−1=(4x−1)(4x+1)16 {x}^{2} - 1 = \left(4 x - 1\right) \left(4 x + 1\right)16x2−1=(4x−1)(4x+1)