factorize 16b^2-81a^2

asked by guest
on Nov 24, 2024 at 12:18 pm



You asked:

Factor the expression: \(\displaystyle 16 {b}^{2} - 81 {a}^{2}\)

MathBot Answer:

The polynomial factors into the product: \[16 {b}^{2} - 81 {a}^{2} = - \left(9 a - 4 b\right) \left(9 a + 4 b\right)\]