(7-2x^2)^2
asked by guest on Apr 07, 2025 at 4:06 am
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MathBot Answer:
(7−2x2)2=(7−2x2)2\displaystyle {\left( 7 - 2 {x}^{2} \right)}^{2} = \left(7 - 2 x^{2}\right)^{2} (7−2x2)2=(7−2x2)2
(7−2x2)2=4x4−28x2+49{\left( 7 - 2 {x}^{2} \right)}^{2} = 4 x^{4} - 28 x^{2} + 49(7−2x2)2=4x4−28x2+49
(7−2x2)2=(2x2−7)2{\left( 7 - 2 {x}^{2} \right)}^{2} = \left(2 x^{2} - 7\right)^{2}(7−2x2)2=(2x2−7)2