ln(1-x)/x-1

asked by guest
on Feb 01, 2025 at 5:07 am



You asked:

Evaluate the expression: ln⁡(1−x)x−1\frac{\ln\left( 1 - x \right)}{x} - 1

MathBot Answer:

Evaluated



ln⁡(1−x)x−1=−1+log⁡(1−x)x\displaystyle \frac{\ln\left( 1 - x \right)}{x} - 1 = -1 + \frac{\log{\left(1 - x \right)}}{x}

Factored

ln⁡(1−x)x−1=−x−log⁡(1−x)x\frac{\ln\left( 1 - x \right)}{x} - 1 = - \frac{x - \log{\left(1 - x \right)}}{x}

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