solve\:for\:x,\:0.63\cdot 100\cdot \:pi\:=\:x^2arccos\left(\frac{x}{20}\right)+2\cdot 100\cdot \left(\frac{pi}{2}-arccos\left(\frac{x}{20}\right)-sin\left(2\cdot \:arccos\left(\frac{x}{20}\right)\right)\right)

asked by guest
on Apr 13, 2025 at 11:37 am



You asked:

Solve the equation 0.63⋅100π=x2arccos⁡(x20)+2⋅100(π2−arccos⁡(x20)−sin⁡(2arccos⁡(x20)))0.63 \cdot 100 \pi = {x}^{2} \arccos\left( \frac{x}{20} \right) + 2 \cdot 100 \left(\frac{\pi}{2} - \arccos\left( \frac{x}{20} \right) - \sin\left( 2 \arccos\left( \frac{x}{20} \right) \right)\right) for the unknown xx.

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