Math Problem Solver

\[ 6\frac{6}{12} + \frac{8}{12} = \frac{43}{6} = 7.1\overline{6} \]

The sum can be computed by rewriting each term over a common denominator, where the least common denominator of \(\frac{6}{1}\), \(\frac{6}{12}\), and \(\frac{8}{12}\) is \(12\). \[ \begin{aligned} 6\frac{6}{12} + \frac{8}{12} &= \frac{6 \cdot 12}{1 \cdot 12} + \frac{6 \cdot 1}{12 \cdot 1} + \frac{8 \cdot 1}{12 \cdot 1} \\ &= \frac{72 + 6 + 8}{12} \\ &= \frac{86}{12} \\&= \frac{43}{6} \end{aligned} \]