$\frac{20x}{x^{2} + 6x + 3}$=0

asked by guest
on Nov 12, 2024 at 3:57 pm



You asked:

Solve the equation \(\frac{20 x}{{x}^{2} + 6 x + 3} = 0\) for the variable \(x\).

MathBot Answer:

The solution is: \[x = 0\]