$$\int_{0.75}^{1.3}((sinx)^2−2xsinx+1) dx$$

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on Oct 26, 2024 at 3:10 am



You asked:

Evaluate the integral: \(\int_{0.75}^{1.3}{{\sin\left( x \right)}^{2} - 2 x \cdot \sin\left( x \right) + 1}dx\)

MathBot Answer:

Definite integral

\[\int_{0.75}^{1.3}{{\sin\left( x \right)}^{2} - 2 x \cdot \sin\left( x \right) + 1}dx = \frac{33}{40} - 2 \sin{\left(\frac{13}{10} \right)} + 2 \sin{\left(\frac{3}{4} \right)} - \frac{3 \cos{\left(\frac{3}{4} \right)}}{2} + \frac{13 \cos{\left(\frac{13}{10} \right)}}{5} + \frac{\cos{\left(\frac{3}{4} \right)} \sin{\left(\frac{3}{4} \right)}}{2} - \frac{\cos{\left(\frac{13}{10} \right)} \sin{\left(\frac{13}{10} \right)}}{2} \approx -0.02037679597887411828821369087495\]

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