\frac{\left(121-100\right)^2}{100}+\frac{\left(288-150\right)^2}{150}+\frac{\left(91-250\right)^2}{250}
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\frac{\left(121-100\right)^2}{100}+\frac{\left(288-150\right)^2}{150}+\frac{\left(91-250\right)^2}{250}
MathBot Answer:
MathBot is working on a solution to your problem.