\frac{\left(121-100\right)^2}{100}+\frac{\left(288-150\right)^2}{150}+\frac{\left(91-250\right)^2}{250}
asked by guest
on Jan 15, 2025 at 5:43 pm
You asked:
Evaluate the expression:
100(121−100)2+150(288−150)2+250(91−250)2
MathBot Answer:
100(121−100)2+150(288−150)2+250(91−250)2=500116247=232.494
100(121−100)2+150(288−150)2+250(91−250)2=100212+150(288−150)2+250(91−250)2=100441+150(288−150)2+250(91−250)2=100441+1501382+250(91−250)2=100441+15019044+250(91−250)2=100441+253174+250(91−250)2=10013137+250(91−250)2=10013137+250−1592=10013137+25025281=500116247