2x³+x²-13x+6
asked by guest on Mar 14, 2025 at 8:05 am
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MathBot Answer:
2x3+x2−13x+6=2x3+x2−13x+6\displaystyle 2 {x}^{3} + {x}^{2} - 13 x + 6 = 2 x^{3} + x^{2} - 13 x + 6 2x3+x2−13x+6=2x3+x2−13x+6
2x3+x2−13x+6=(2x−1)(x−2)(x+3)2 {x}^{3} + {x}^{2} - 13 x + 6 = \left(2 x - 1\right) \left(x - 2\right) \left(x + 3\right)2x3+x2−13x+6=(2x−1)(x−2)(x+3)