Math Problem Solver

\[ 53 + 4\frac{3}{7} = \frac{402}{7} = 57.\overline{428571} \]

The sum can be computed by rewriting each term over a common denominator, where the least common denominator of \(\frac{53}{1}\), \(\frac{4}{1}\), and \(\frac{3}{7}\) is \(7\). \[ \begin{aligned} 53 + 4\frac{3}{7} &= \frac{53 \cdot 7}{1 \cdot 7} + \frac{4 \cdot 7}{1 \cdot 7} + \frac{3 \cdot 1}{7 \cdot 1} \\ &= \frac{371 + 28 + 3}{7} \\ &= \frac{402}{7} \end{aligned} \]