(120 $x^{2}$)/(x-0.2)-4.8/(x-0.2)-4.8x/(x-0.2)+9.6/(x-0.2)-43.2/(0.6-x)+120$x^{2}$/(0.6-x)+86.4/(0.6-x)-144x/(0.6-x)=48

asked by guest
on May 28, 2025 at 3:46 pm



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