0,1*pi/ln2

asked by guest
on Nov 19, 2024 at 4:25 am



MathBot Answer:

The sum of \(0\) and \(\frac{1 \cdot \pi}{\ln\left( 2 \right)}\) is:

\[\begin{aligned}&=\left(0\right) + \left(\frac{1 \cdot \pi}{\ln\left( 2 \right)}\right) \\\\ &= 1 \pi \frac{1}{\log{\left(2 \right)}} \\\\ &= \frac{\pi}{\log{\left(2 \right)}} \\\\\end{aligned}\]

The difference of \(0\) and \(\frac{1 \cdot \pi}{\ln\left( 2 \right)}\) is:

\[\begin{aligned}&=\left(0\right) - \left(\frac{1 \cdot \pi}{\ln\left( 2 \right)}\right) \\\\ &= - \frac{\pi}{\log{\left(2 \right)}} \\\\\end{aligned}\]

The product of \(0\) and \(\frac{1 \cdot \pi}{\ln\left( 2 \right)}\) is:

\[\begin{aligned}&=\left(0\right) \cdot \left(\frac{1 \cdot \pi}{\ln\left( 2 \right)}\right) \\\\ &= 0 \\\\\end{aligned}\]

The quotient of \(0\) and \(\frac{1 \cdot \pi}{\ln\left( 2 \right)}\) is:

\[\begin{aligned}&= \frac{\left(0\right)}{\left(\frac{1 \cdot \pi}{\ln\left( 2 \right)}\right)} \\\\ &= 0 \\\\\end{aligned}\]

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