1x\frac{1}{x}x1< 1x−3\frac{1}{x-3}x−31 + x2−1x2−3x\frac{x^2-1}{x^2-3x}x2−3xx2−1
asked by guest on Apr 04, 2025 at 8:47 am
You asked:
MathBot Answer:
x<0∧x>3x < 0 \wedge x > 3x<0∧x>3