1/(x+3)+1/(x-3)=6/(x^2-9)

asked by guest
on Oct 26, 2024 at 8:38 am



You asked:

Solve the equation \(\frac{1}{x + 3} + \frac{1}{x - 3} = \frac{6}{{x}^{2} - 9}\) for the variable \(x\).

MathBot Answer:

No solution.

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