cos(2x+3y)−xsin(2x+3y)(2+3

dx

dy

​

)=

dx

dy

​

sinx+ycosx

asked by guest
on Nov 15, 2024 at 11:33 am



You asked:

Investigate the equation: cos⁡(2x+3y)−xsin⁡(2x+3y)(2+3dxdy)=dxdysin⁡(x)+ycos⁡(x)\cos\left( 2 x + 3 y \right) - x \sin\left( 2 x + 3 y \right) \left(2 + 3 d x d y\right) = d x d y \sin\left( x \right) + y \cos\left( x \right).

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