64^ x\sqrt{x} = 32\sqrt{32}

asked by guest
on Nov 18, 2024 at 11:11 pm



You asked:

Solve the equation 64x=32{64}^{\sqrt{x}} = \sqrt{32} for the variable xx.

MathBot Answer:

The solution is: x=log⁡(42)2log⁡(64)2≈0.17361111x = \frac{\log{\left(4 \sqrt{2} \right)}^{2}}{\log{\left(64 \right)}^{2}} \approx 0.17361111

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