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p(7) = 50,000e ^0.018(7) e^x = 1+x+x^2 over 2!
asked by
guest
on Mar 13, 2025 at 12:30 am
You asked:
Solve the system of equations:
e
x
=
1
+
x
+
x
2
2
!
p
(
7
)
=
50
,
000
e
0.018
⋅
7
\begin{aligned}{e}^{x} &= 1 + x + \frac{{x}^{2}}{2!}\\p\left( 7 \right) &= 50,000 {e}^{0.018} \cdot 7\end{aligned}
e
x
p
(
7
)
=
1
+
x
+
2
!
x
2
=
50
,
000
e
0.018
⋅
7
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