x^2-x-2y=0;y^2-2y-3z=0;z^2-3z-x=0
You asked:
Solve the system of equations:\[\begin{aligned}{x}^{2} - x - 2 y &= 0\\{y}^{2} - 2 y - 3 z &= 0\\{z}^{2} - 3 z - x &= 0\end{aligned}\]
MathBot Answer:
The system of equations has \(2\) solutions.
\[x = -2, y = 3, z = 1\]\[x = 0, y = 0, z = 0\]