4^(x+1)=2-7(2^x)

asked by guest
on Jan 10, 2025 at 5:32 pm



You asked:

Solve the equation \({4}^{x + 1} = 2 - 7 \cdot {2}^{x}\) for the variable \(x\).

MathBot Answer:

The solution is: \[x = -2\]

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