b^-3/c^-3 * (b/c)^-3
asked by guest on Feb 01, 2025 at 3:04 am
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MathBot Answer:
b−3c−3(bc)−3=c6b6\frac{{b}^{-3}}{{c}^{-3}} {\left( \frac{b}{c} \right)}^{-3} = \frac{c^{6}}{b^{6}}c−3b−3(cb)−3=b6c6