$\frac{\1}{\1+tanx}$ $\frac{\1}{\1+cotx}$

asked by guest
on Oct 26, 2024 at 1:31 pm



You asked:

Evaluate the expression: \(\frac{1}{1 + \tan\left( x \right)} \cdot \frac{1}{1 + \cot\left( x \right)}\)

MathBot Answer:

Evaluated



\(\displaystyle \frac{1}{1 + \tan\left( x \right)} \cdot \frac{1}{1 + \cot\left( x \right)} = \frac{1}{\left(\tan{\left(x \right)} + 1\right) \left(\cot{\left(x \right)} + 1\right)} \)

Expanded

\[\frac{1}{1 + \tan\left( x \right)} \cdot \frac{1}{1 + \cot\left( x \right)} = \frac{1}{\tan{\left(x \right)} \cot{\left(x \right)} + \tan{\left(x \right)} + \cot{\left(x \right)} + 1}\]

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