$\frac{\1}{\1+tanx}$ $\frac{\1}{\1+cotx}$
You asked:
Evaluate the expression: \(\frac{1}{1 + \tan\left( x \right)} \cdot \frac{1}{1 + \cot\left( x \right)}\)
MathBot Answer:
Evaluated
\(\displaystyle \frac{1}{1 + \tan\left( x \right)} \cdot \frac{1}{1 + \cot\left( x \right)} = \frac{1}{\left(\tan{\left(x \right)} + 1\right) \left(\cot{\left(x \right)} + 1\right)} \)
Expanded
\[\frac{1}{1 + \tan\left( x \right)} \cdot \frac{1}{1 + \cot\left( x \right)} = \frac{1}{\tan{\left(x \right)} \cot{\left(x \right)} + \tan{\left(x \right)} + \cot{\left(x \right)} + 1}\]