Math Problem Solver

$$\frac{1}{3} + \frac{4}{6} = 1$$

The sum can be computed by rewriting each term over a common denominator, where the least common denominator of $\frac{1}{3}$ and $\frac{4}{6}$ is $6$. $$\begin{aligned} \frac{1}{3} + \frac{4}{6} &= \frac{1 \cdot 2}{3 \cdot 2} + \frac{4 \cdot 1}{6 \cdot 1} \\ &= \frac{2 + 4}{6} \\ &= \frac{6}{6} \\&= 1 \end{aligned}$$