b^2\left[\frac{\pi }{4}-\:arcos\left(\frac{15\sqrt{2}}{2b}\right)\right]+\left(\frac{15\sqrt{2}}{2}\right)\sqrt{b^2-\frac{225}{2}}=101.25
You asked:
Investigate the equation: .
b^2\left[\frac{\pi }{4}-\:arcos\left(\frac{15\sqrt{2}}{2b}\right)\right]+\left(\frac{15\sqrt{2}}{2}\right)\sqrt{b^2-\frac{225}{2}}=101.25
You asked: