if p(x)=x³-ax²+bx+3 leaves a remainder -19 when divided by x+2 and a remainder 17 when divided by x-2 prove that a+b=6
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if p(x)=x³-ax²+bx+3 leaves a remainder -19 when divided by x+2 and a remainder 17 when divided by x-2 prove that a+b=6
I wasn't able to parse your question, but the HE.NET team is hard at work making me smarter.