$3^{x}$+ $3^{x-1}$ + $3^{x-2}$ + $3^{x-3}$ + $3^{x-4}$ $3^{x-5}$ =1092

asked by guest
on Oct 24, 2024 at 10:31 am



You asked:

Solve the equation \({3}^{x} + {3}^{x - 1} + {3}^{x - 2} + {3}^{x - 3} + {3}^{x - 4} \cdot {3}^{x - 5} = 1092\) for the variable \(x\).

MathBot Answer:

The solution is: \[x = \frac{\log{\left(-14580 + 486 \sqrt{991} \right)}}{\log{\left(3 \right)}} \approx 5.9878756\]