0,425*(3/1)*(2/1)

asked by guest
on Apr 25, 2024 at 7:56 am

MathBot Answer:

The sum of \(0\) and \(425 \cdot \frac{3}{1} \cdot \frac{2}{1}\) is:

\[\begin{aligned}&=\left(0\right) + \left(425 \cdot \frac{3}{1} \cdot \frac{2}{1}\right) \\\\ &= 425 \cdot 3 \cdot 1^{-1} \cdot 2 \cdot 1^{-1} \\\\ &= 2550 \\\\\end{aligned}\]


The difference of \(0\) and \(425 \cdot \frac{3}{1} \cdot \frac{2}{1}\) is:

\[\begin{aligned}&=\left(0\right) - \left(425 \cdot \frac{3}{1} \cdot \frac{2}{1}\right) \\\\ &= \left(-1275\right) 1^{-1} \cdot 2 \cdot 1^{-1} \\\\ &= -2550 \\\\\end{aligned}\]


The product of \(0\) and \(425 \cdot \frac{3}{1} \cdot \frac{2}{1}\) is:

\[\begin{aligned}&=\left(0\right) \cdot \left(425 \cdot \frac{3}{1} \cdot \frac{2}{1}\right) \\\\ &= 0 \\\\\end{aligned}\]


The quotient of \(0\) and \(425 \cdot \frac{3}{1} \cdot \frac{2}{1}\) is:

\[\begin{aligned}&= \frac{\left(0\right)}{\left(425 \cdot \frac{3}{1} \cdot \frac{2}{1}\right)} \\\\ &= 0 \\\\\end{aligned}\]

asked 9 days ago

active 9 days ago