0,425*(3/1)*(2/1)
MathBot Answer:
The sum of \(0\) and \(425 \cdot \frac{3}{1} \cdot \frac{2}{1}\) is:
\[\begin{aligned}&=\left(0\right) + \left(425 \cdot \frac{3}{1} \cdot \frac{2}{1}\right) \\\\ &= 425 \cdot 3 \cdot 1^{-1} \cdot 2 \cdot 1^{-1} \\\\ &= 2550 \\\\\end{aligned}\]
The difference of \(0\) and \(425 \cdot \frac{3}{1} \cdot \frac{2}{1}\) is:
\[\begin{aligned}&=\left(0\right) - \left(425 \cdot \frac{3}{1} \cdot \frac{2}{1}\right) \\\\ &= \left(-1275\right) 1^{-1} \cdot 2 \cdot 1^{-1} \\\\ &= -2550 \\\\\end{aligned}\]
The product of \(0\) and \(425 \cdot \frac{3}{1} \cdot \frac{2}{1}\) is:
\[\begin{aligned}&=\left(0\right) \cdot \left(425 \cdot \frac{3}{1} \cdot \frac{2}{1}\right) \\\\ &= 0 \\\\\end{aligned}\]
The quotient of \(0\) and \(425 \cdot \frac{3}{1} \cdot \frac{2}{1}\) is:
\[\begin{aligned}&= \frac{\left(0\right)}{\left(425 \cdot \frac{3}{1} \cdot \frac{2}{1}\right)} \\\\ &= 0 \\\\\end{aligned}\]
asked 9 days ago
active 9 days ago