2^x = (-5 ± √79i)/2
You asked:
Investigate the equation: \({2}^{x} = \frac{-5 \pm \sqrt{79} \cdot i}{2}\).
MathBot Answer:
This question involves the \(\pm\) operator. There are \(2\) variations to solve.
Answer summary:
No solution.
No solution.
Variation \(1\) of \(2\)
Solving: \(\displaystyle 2^{x}=\frac{\sqrt{79}i+-5}{2}\)
No solution.
\(i\) is the imaginary unit, defined as \(i^2 = -1\).
Variation \(2\) of \(2\)
Solving: \(\displaystyle 2^{x}=\frac{-\sqrt{79}i+-5}{2}\)
No solution.
\(i\) is the imaginary unit, defined as \(i^2 = -1\).