2^x = (-5 ± √79i)/2

asked by guest
on Nov 17, 2024 at 2:36 am



You asked:

Investigate the equation: 2x=5±79i2{2}^{x} = \frac{-5 \pm \sqrt{79} \cdot i}{2}.

MathBot Answer:

This question involves the ±\pm operator. There are 22 variations to solve.
Answer summary:

No solution.

No solution.


Variation 11 of 22


Solving: 2x=79i+52\displaystyle 2^{x}=\frac{\sqrt{79}i+-5}{2}

No solution.


ii is the imaginary unit, defined as i2=1i^2 = -1.


Variation 22 of 22


Solving: 2x=79i+52\displaystyle 2^{x}=\frac{-\sqrt{79}i+-5}{2}

No solution.


ii is the imaginary unit, defined as i2=1i^2 = -1.