1+2+3+4...+100

asked by guest
on Oct 21, 2024 at 5:06 pm



You asked:

Find the sum of the sequence: \(1\), \(2\), \(3\), \(4\), \(\ldots\), \(100\)

MathBot Answer:

The sum of the sequence is \(\displaystyle 5050\)


This is an arithmetic sequence.

The nth term in this sequence is given by the formula:

Explicit Formula: $$a_n=n$$

Recursive Formula: $$a_n=a_{n-1} + 1, \text{where } a_1=1$$


Summation Formula:

Option 1:

$$S_n=\frac{n}{2} (2 a_1 + (n - 1) d)$$ where $a_1$ is the 1st term, $d$ is the common difference, and $n$ is the is the term number.

Option 2:

$$S_n=n \left(\frac{a_1 + a_n}{2}\right)$$ where $a_1$ is the 1st term, $a_n$ is the nth term, and $n$ is the is the term number.

Option 3:

$$\begin{aligned} S_n&=\sum_{i=1}^{n} a_{i} \\ &=\sum_{i=1}^{n} i \\ &=\frac{n \left(n + 1\right)}{2} \end{aligned}$$where $n$ is the is the term number.


Use the explicit formula to find the index of the final term in the sequence.$$\begin{aligned}100 &= n \\ n &= 100\end{aligned}$$Then use the summation formula to solve.$$\begin{aligned}S_n &= \frac{n \left(n + 1\right)}{2} \\S_{100} &= \frac{100 \cdot \left(1 + 100\right)}{2}\\S_{100} &= 5050\end{aligned}$$