solve for x:
$7^{2x+1}$ = $4^{x-2}$
You asked:
Solve the equation \[{7}^{2 x + 1} = {4}^{x - 2}\] for the unknown \(x\).
MathBot Answer:
The solution is: \[x = \frac{\log{\left(112 \right)}}{2 \left(- \log{\left(7 \right)} + \log{\left(2 \right)}\right)} \approx -1.8832369\]