When 0° ≤ θ ≤ 90°, then solution of cos²θ + sinθ – 2 = 0

is:

(a) θ=0° or 30° (b) θ=60° or 45°

(c) θ=45° or 90° (d) θ=60° or 90°

asked by guest
on Feb 22, 2026 at 1:59 am



MathBot Answer:

MathBot is working on a solution to your problem.

Loading bar

+ Submit Question