2*3^n-1=1458

asked by guest
on Nov 18, 2024 at 5:50 am



You asked:

Solve the equation \(2 \cdot {3}^{n} - 1 = 1458\) for the variable \(n\).

MathBot Answer:

The solution is: \[n = \frac{\log{\left(\frac{1459}{2} \right)}}{\log{\left(3 \right)}} \approx 6.0006241\]

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