(x-2)^2+(y-3)^2=10
You asked:
Investigate the equation: \({\left( x - 2 \right)}^{2} + {\left( y - 3 \right)}^{2} = 10\).
MathBot Answer:
The graph of the equation \({\left( x - 2 \right)}^{2} + {\left( y - 3 \right)}^{2} = 10\) is a circle.
The coordinates of its center are \(\left(2, 3\right)\).
Its radius is \(\sqrt{10}\).
The cirlce has parameterization: \[\begin{aligned}x\left(\theta\right) &= 2 + \sqrt{10} \cos{\left(\theta \right)}\\y\left(\theta\right) &= 3 + \sqrt{10} \sin{\left(\theta \right)}\end{aligned}\]