\int _1^2\:\left(5x^{-4}-8x^{-3}\right)dx

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on Apr 01, 2025 at 1:00 pm



You asked:

Evaluate the integral: ∫125x−4−8x−3dx\int_{1}^{2}{5 {x}^{-4} - 8 {x}^{-3}}dx

MathBot Answer:

Definite integral

∫125x−4−8x−3dx=−3724=−1.5416‾\int_{1}^{2}{5 {x}^{-4} - 8 {x}^{-3}}dx = - \frac{37}{24} = -1.541\overline{6}

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