16-2r=-3r+6r+1

asked by guest
on Nov 29, 2024 at 9:28 pm



You asked:

Solve the equation \(16 - 2 r = -\left( 3 r \right) + 6 r + 1\) for the variable \(r\).

MathBot Answer:

The solution is: \[r = 3\]


\[\begin{aligned}16 - 2 r &= -\left( 3 r \right) + 6 r + 1\\16 - 2 r &= 3 r + 1\\- 5 r &= -15\\r &= 3\end{aligned}\]