((x^2 - 4)/(x - 1) - 2*x*ln(x - 1) + 2*x)/((x^2 - 4)^2) = 0

asked by guest
on Nov 26, 2024 at 10:18 am



You asked:

Solve the equation x2−4x−1−2xln⁡(x−1)+2x(x2−4)2=0\frac{\frac{{x}^{2} - 4}{x - 1} - 2 x \ln\left( x - 1 \right) + 2 x}{{\left( {x}^{2} - 4 \right)}^{2}} = 0 for the variable xx.

MathBot Answer:

The complex solutions are: {x  |  x∈R∧2x2log⁡(x−1)−3x2−2xlog⁡(x−1)+2x+4=0}∖{−2,1,2}\left\{x\; \middle|\; x \in \mathbb{R} \wedge 2 x^{2} \log{\left(x - 1 \right)} - 3 x^{2} - 2 x \log{\left(x - 1 \right)} + 2 x + 4 = 0 \right\} \setminus \left\{-2, 1, 2\right\}

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