x^2-4x/4x
asked by guest on Jan 28, 2025 at 10:03 pm
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MathBot Answer:
x2−4x4x=x2−1\displaystyle {x}^{2} - \frac{4 x}{4 x} = x^{2} - 1 x2−4x4x=x2−1
x2−4x4x=(x−1)(x+1){x}^{2} - \frac{4 x}{4 x} = \left(x - 1\right) \left(x + 1\right)x2−4x4x=(x−1)(x+1)